Cl2 + NaI = NaCl + I2

Balanced Chemical Equation – Solution

Cl2 + 2NaI → 2NaCl + I2

The coefficients show the number of particles (atoms or molecules), and the indices show the number of atoms that make up the molecule. New substances are formed as a result of the rearrangement of the original atoms. As a result of a chemical reaction, atoms of chemical elements do not disappear anywhere and new ones do not appear, their number remains unchanged – this follows from the law of conservation of mass of substances.

Chemical Reaction Information

Dichlorine + Sodium Iodide = Sodium Chloride + Diiodine

This is an oxidation-reduction (redox) reaction. Cl2 is an oxidizing agent, NaI is a reducing agent.

  • 2 Cl0 + 2 e  2 Cl-I (reduction)
  • 2 I-I  2 e  2 I0 (oxidation)

Reaction Type

Single Displacement (Substitution)

Substances that react are called starting materials or reactants. The substances that form as a result are called reaction products.



  • Names: Chlorine.
  • Appearance: Greenish-yellow compressed liquefied gas with pungent odour.


  • Names: Sodium iodide.
  • Appearance: White solid | deliquescent.


NaCl – Sodium chloride

  • Appearance: Colorless cubic crystals


  • Names: Iodine.
  • Appearance: Bluish black or dark purple crystals with pungent odour.
Similar Examples of Equalizing a Chemical Reaction
H2O + Cl2 + NaI → HCl + NaIO3
Cl2 + NaI → I2 + NaCl
Cl2 + NaI + CCl4 → I2 + NaCl + C2

Alexander Stephenson

Candidate of Chemical Sciences, editor-in-chief of Lecturer at several international online schools, member of the jury of chemistry competitions and author of scientific articles.

Rate author

Leave a Reply